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First steps

Let suppose that we focus our scientific curiosity on the concept of “division” and that we must explain it to someone else. We would probably start with a simple question like: “What do you find when you divide six by three?” Most of the spontaneous answers will be: 2. But why? And the next answer would certainly come: “It’s natural!”. And, as a matter of facts, 2, 3 and 6 are natural numbers with which we are seemingly customized to count.

Unfortunately for those who are looking for the simplicity, and as one teaches it in schools, there are a lot of other categories of numbers: relative natural: Z = {-…, -2, -1, 0, 1, 2, …}, fractional: Q ={…-5/17, …, 9/253, …}, real: R, complex: C, etc. Therefore, the next question is: “Why did nobody give the following answers to my question: 6 = ½. 3 + 9/2 or 6 = 2,3. 3 - 0,9?” These answers would also have been correct because, my fault, I haven’t precise an important parameter in my initial question: “What do you find when you divide six by 2 and your answer must be a fractional number (respectively a real number, etc.)?” So: I should have first given information on the set in which the solution(s) must be.

What do we state next? The answers are, most of the time, far to be unique; and what else? Any correct answer is not only made of one number, but of a pair of numbers which we may generically label (the main result, the remaining part).

The trivial answer accompanying the answer when we stay in N = {0, 1, ….} is misleading our thoughts on the topic because it gives us the sensation that all responses contain only one number. The correct answer to my initial and quasi-naïve question when the solutions must be in N should have been the pair: (2, 0). It is just because there is no remaining part that we didn’t realize the duality of the answer.

These basic, but in some way fundamental elements of a discussion about the concept of division, can now be extrapolated. We may ask if we can divide six by a vector, for example? Or we can consider any vector and ask if we can decompose it with a matrix? These interrogations would slowly drive the discussion into the direction of the concept of torsion or an abstract generalization of it.

These first paragraphs, here, are only a short presentation of what is waiting for you on this website if you want to deepen the mathematics illustrating these preliminaries; they are the essence of the theory of the (E) question (alias TEQ).

© by Thierry PERIAT: The Theory of the (E) question – Semantic

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Peculiar terms

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Comments

Products and their extensions

Tensor product

See any good book or, as first help:

the extern link on Wikipedia – GB

The operator is denoted Ä(…, …)

Projectile

First argument:  Ä(Projectile, …)

Target

Second argument: Ä(…, Target)

Cube

Within the theory of deformed tensor products, a cube should be understood as a mathematical object fulfilled with elements of a given set K placed at the different knots of a Euclidean cubic crystal. It may also be represented as a superposition of matrices disposed in a three-dimensional non-deformed Euclidean space. Although the analogy with a connection is obvious, it should not systematically and a priori be identified with.

Symmetric

A cube is symmetric when: Aijk = Ajik

Anti-symmetric

A cube is symmetric when: Aijk + Ajik = 0

Reduced

A cube is reduced when: Aiki = Aijk

Anti-reduced

A cube is anti-reduced when: Aijk + Aikj = 0

Symmetric and reduced

Anti-symmetric and anti-reduced

Null

Hypercube

A hyper-cube is a generalization of the concept of cube to a space with a physical dimension greater than three.

Deformed tensor product

A deformed tensor product is a classical tensor product that has been deformed by a cube

The cubes are deforming the classical tensor products acting on a vector space E(D, K) because they are modifying their usual definition as follows:

ÄA(a, b) = Aijk. ai. bj. ek

Where the ek are the basis vector of E(D, K).

 Deformed exterior product

Following an historical way of doing, a deformed exterior product is:

ÙA(a, b)

=

ÄA(a, b) - ÄA(b, a)

=

Aijk. (ai. bj - bi. aj). ek

Deformed Lie product

A deformed Lie product is a deformed exterior product built on an anti-symmetric cube

Elements of a decomposition

Intrinsic ingredients

Projectile, target and cube are the intrinsic elements in a mathematical problem (The so-called (E) question) asking for the existence and the formalism of pairs ([P], z) such that:

A(a, b) > = [P]. |b > + |z > Î E*(D, K)

Main part

([P], …) is the main part in a decomposition ([P], z).

This is an element of M(D, K)

Residual part

(…, z) is the residual part in a

decomposition ([P], z); this is an element in E(D, K)

Trivial

A decomposition is said to be trivial when:

A(a, b) > = [P]. |b > + |0 >

Non-trivial

A decomposition is non-trivial when its residual part doesn’t vanish.

Methods

of decomposition

Intrinsic

An intrinsic method of decomposition is a mathematical method allowing the discovery of one or several pair(s) ([P], z) with the help of intrinsic ingredients only. Up to now, I have only done in in a three-dimensional context for deformed Lie products.

Extrinsic

An extrinsic method of decomposition is any mathematical method offering an answer to the (E) question with the help of ingredients which are not only intrinsic to the question.

Russian dolls

The Russian dolls method is inspired by the well-known traditional objects and describes any procedure allowing the discovery of decompositions when the (E) question is asked in E(D + 1, K) but has been answered in E(D, K).

© Thierry PERIAT

event Date de dernière mise à jour : 09/09/2020

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